7+3√5/7-3√5
rationalize
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7' 457 ( 1235,)00000000
kangdaniel:
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(7+3√5)/(7-3√5)
By rationalising the denominator,
(7+3√5)(7+3√5)/(7-3√5)(7+3√5)
=(7+3√5)²/(7)²-(3√5)²
=(49+45+42√5)/49-45
=(94+42√5)/4
=(47+21√5)/2
Hope its correct
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