Α Α Α
+
7
+
Α Α
=3 7 3
Answers
Answered by
1
Let P=(1,0,3),Q=(
3
5
,
3
7
,
3
17
),A=(α,7,1)
Here
PQ
is perpendicular to
QA
∴
PQ
.
QA
=0
⇒(1−
3
5
)(α−
3
5
)+(
3
−7
)(7−
3
7
)+(3−
3
17
)(1−
3
17
)=0
3
−2α
+
9
10
−
9
98
+
9
112
=0
α=4
solution
I hope you are understand my solution
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