Question

7+4root3+( (2)^2-(root3)^2)-7-4root3. please step by step

Answer 1

Answer:

1

Step-by-step explanation:

7+4root3+( (2)^2-(root3)^2)-7-4root3

$7 + 4\sqrt{3} + (2^{2} - \sqrt{3}^{2} ) - 7 - 4\sqrt{3} \\= 7 + 4\sqrt{3} + 4 - 3 - 7 - 4\sqrt{3} \\= 7 - 7 + 4\sqrt{3} - 4\sqrt{3} + 4 - 3\\= 1$