Question

7,8,9,10 this question solutions please ​

Answer 1

Answer:

H.C.F are

(vii)-24

(viii)-5

(ix)-10

(x)-15

Step-by-step explanation:

(vii) 240 and 6552

as 6552>240

by applying Euclid's division algorithm we get

6552=240x27+72

=>240=72x3+24

=>72=24x3+0

therefore 24 is the H.C.F of 240 and 6552

(viii) 155 and 1385

as 1385> 155

1385=155x8+145

=>155=145x1+10

=>145=10x14+5

=>10=5x2+0

therefore 5 is the H.C.F of 155 and 1385

(ix)100 and 190

as 190>100

190=100x1+90

=>100=90x1+10

=>90=10x9+0

therefore 10 is the H.C.F of 100 and 190

(x)105 and 120

as 120> 105

120=105x1+15

=>105=15x7+0

therefore 15 is the H.C.F of 105 and 120

If you are studying in s.t.d-10 then u can understand it easily ☺️