Math, asked by ranjitkumardv, 3 months ago

7. A alone can do a piece of work in 12 days and B along can do the same work in 15 days. They start workin
together. After 4 days B leaves the work. In how many days A alone complete the remaining work?

Answers

Answered by Anonymous
1

Answer = 18 days

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Answered by Anonymous
1

Step-by-step explanation:

Consider eating 60 ( L.C.M of 12 and 15 - for easy canculation. You can assume any number) candies is the above said work.

Consider eating 60 ( L.C.M of 12 and 15 - for easy canculation. You can assume any number) candies is the above said work.A takes 12 days to eat 60 candies. ie, A eats 5 candies per day. Similarly, B eats 4 candies per day. Together they eat 9 candies per day.

Consider eating 60 ( L.C.M of 12 and 15 - for easy canculation. You can assume any number) candies is the above said work.A takes 12 days to eat 60 candies. ie, A eats 5 candies per day. Similarly, B eats 4 candies per day. Together they eat 9 candies per day.They work together for 4 days. ie, 4 x 9 = 36 candies. Now 24 candies are left. These 24 candies have to be eaten by A only.

Consider eating 60 ( L.C.M of 12 and 15 - for easy canculation. You can assume any number) candies is the above said work.A takes 12 days to eat 60 candies. ie, A eats 5 candies per day. Similarly, B eats 4 candies per day. Together they eat 9 candies per day.They work together for 4 days. ie, 4 x 9 = 36 candies. Now 24 candies are left. These 24 candies have to be eaten by A only.A eats 5 candies per day. So A will require 24/5 days to eat the remaining candies.

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