Question

7. A ball is gently dropped from a height of 20 m. If its velocity
increases uniformly at the rate of 10 ms^-2, with what velocity
will it strike the ground? After what time will it strike the
ground?​

Answer 1

Answer:

v²=u²+2as

v²=0+2*10*20

v²=400

v=20m/s

Explanation:

u=o because ball is simply dropped

Answer 2

Answer:

Given, initial velocity of ball, u=0

Final velocity of ball, v=?

Distance through which the balls falls, s=20m

Acceleration a=10ms

−2

Time of fall, t=?

We know

v

2

−u

2

=2as

or v

2

−0=2×10×20=400 or v=20ms

−1

Now using v=u+at we have

20=0+10×t or t=2s

20m/s,2s

Explanation:

Its help you to solve