Question

7) A body is projected horizontally with a velocity of 4 m/s. The velocity of the body after 0.7 secs is
(Take g 10 m/s)

Answer 1

Explanation:

After 0.7 sec, the horizontal velocity component of the body = 4√2 m/sec, since there is no change in velocity in horizontal direction. The vertical velocity component after 0.7 seconds, v = 0 + gt = 0 + 0.7 x 10 = 7 m/sec Resultant velocity of the body Read more on Sarthaks.com - https://www.sarthaks.com/245153/body-is-projected-horizontally-with-velocity-42-sec-the-velocity-the-body-after-seconds

Answer 2

Given :-

Velocity in horizontal direction = Vx = 4 m/s.

Velocity in vertical direction = Vy = gt = 10 × 0.7 = 7 m/s

|V| = √(Vx)² + (Vy)²

|V| = √4² + 7²

|V| = √16 + 49

|V| = √65

|V| = 8.1 ms-¹.

Hence,

The velocity of ball after 0.7 s = 8.1 ms-¹.