Physics, asked by ayushkumar2305, 1 year ago

the specific gravity of ice is 0.9. Find the area(in m^2) of the smallest slab of ice of height 0.5m floating in fresh water,that will just support a 100kg man.​

Answers

Answered by arihantjaon042006
3

Answer:

2M^2

Explanation:

Answered by arunsomu13
7

Answer:

2m^2

Explanation:

on equating the forces;

900(0.5)(A)g= force on ice block downward

100g= force on man downward

1000(0.5)(A)g= buoyant force on the block upward

we get : 900(0.5)(A)g+ 100g = 1000(0.5)(A)g

            A=2m^2

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