the specific gravity of ice is 0.9. Find the area(in m^2) of the smallest slab of ice of height 0.5m floating in fresh water,that will just support a 100kg man.
Answers
Answered by
3
Answer:
2M^2
Explanation:
Answered by
7
Answer:
2m^2
Explanation:
on equating the forces;
900(0.5)(A)g= force on ice block downward
100g= force on man downward
1000(0.5)(A)g= buoyant force on the block upward
we get : 900(0.5)(A)g+ 100g = 1000(0.5)(A)g
A=2m^2
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