Question

7. A box contains 4 red balls, 3 blue balls and 2 white balls. If a ball is now drawn at random from this
box. Find the probability that this ball is (i) white (ii) blue (ul) not red.​

Answer 1

A box contains 4 red balls, 3 blue balls and 2 white balls. If a ball is now drawn at random from this

box. Find the probability that this ball is (i) white (ii) blue (iii) not red.

Step-by-step explanation:

No. of red balls = 4

No. of blue balls = 3

No. of white balls = 2

Sol -- P(E) = $\frac{Number of a Favourable outcome}{Total number of outcomes}$

P = n (E) / n (S)

I ] P(E) of getting white balls is

$\frac{2}{9}$

II ]P(E) of getting blue balls is

$\frac{3}{9}$$\cancel\frac{{3}}{{9}}$

= $\frac{1}{3}$

III ]P(E) of getting not red is 9 - 4 / 9

$\frac{5}{9}$

Answer 2

♋♋YOUR ANSWERS♍♍

✍ (i)=2/9 , (ii)=1/3 , (iii)= 5/9

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EXPLANATION —

$Probability = \frac{favourable \: outcomes}{Total \: outcomes }$

Given —

Red Balls = 4

Blue Balls = 3

White Balls = 2

____________________________

Since, total number of balls = 4+3+2 =9

____________________________

(i) Number if white balls = 2

Therefore, probability of getting a white ball = 2/9

____________________________

(ii)Number of blue balls = 3

Therefore, probability of getting a blue ball = 3/9 = 1/3

______________________________

(iii) Number of balls other than red = 9 - 4 = 5

Therefore, probability of getting a no red ball = 5/9

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