Question

7. A car starts from rest and moves along the x-axis
with constant acceleration 5 ms2 for 8 seconds. If it
then continues with constant velocity, what distance
will the car cover in 12 seconds since it started from
rest?
(1) 160 m
(2) 200 m
(3) 320 m (4) 400 m​

Answer 1

Answer:

2= 200 m. ........

Answer 2

(1) 160m

s = ut + 1/2at^2

s =(0)(8) + 1/2(5)(8)^2

s =0 + 1/2(5)(64)

s =0 + 160

s = 160m

If t = 12 sec,

s = ut + 1/2at^2

s = (0)(12) + 1/2(5)(12)^2

s = 0 + 1/2(5)(144)

s = 0 + 360

s = 360m