Question

7. A chord of a circle of radius 12 cm subtends an
angle of 120° at the centre. Find the area of the
corresponding segment of the circle.
(Use
$\pi = 3.14 \: \:and \: \sqrt{3 } = 1.73$
​

Answer 1

in given circle

radius (r)=12

Theta =120°

area of segment APB=

area of sector OAPB - area of triangle AOB ......i

area of sector OAPB= theta x πr^2

360°

solve it

answer=150.72cm^2

area of triangle AOB=

area of right triangle AOM +area of right triangle BOM

solve it

answer=62.28cm^2

put values in equation i

answer. ==== 150.72 - 68.28

== 88.44cm^2