Question

7. A milkman sold two of his buffaloes for ₹ 20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss.

(Hint: Find CP of each)

drop some ❤❤ plz ..

Answer 1

Step-by-step explanation:

Selling price of 1st buffalo = Rs.20000

He made a gain of 5% in 1st buffalo

Cost price of 1st buffalo = (100/105) x 20000 = Rs. 19047.62

Selling price of 2nd buffalo = Rs.20000

He made a loss of 10% in 2nd buffalo

Cost price of 2nd buffalo = (100/90) x 20000 = Rs. 22222.22

Total C.P = 19047.62 + 22222.22 = Rs. 41269.84

Total S.P. = 20000 + 20000 = Rs.40000

Therefore, Loss = 41269.84 – 40000 = Rs.1269.84

hope this helps you dear

kk

Answer 2

Given:-

• Cost of each Buffalo is ₹20000 each.
• On one he made 5% gain.
• On other he made a loss of 10%.

To find:-

• Gain or loss%.

Solution:-

We will first calculate the CP for the first Buffalo.

$\large{\bf{ \longmapsto \frac{5}{100} \times 20000 }}$

$\large\underline{\bf{ \longmapsto 1000}}$

$\large\underline{\bf{ \longmapsto 20000 + 1000}}$

$\large\underline{ \boxed{\bf{ \implies₹21000}}}$

Now we will calculate the CP for the second Buffalo.

$\large{\bf{ \longmapsto \frac{10}{100} \times 20000 }}$

$\large\underline{\bf{ \longmapsto2000}}$

$\large\underline{\bf{ \longmapsto20000 - 2000}}$

$\large\underline{ \boxed{\bf{ \implies₹18000}}}$

Finding overall gain or loss %.

$\large{\bf{ \longmapsto \frac{18000 + 21000}{20000 + 20000} \times 100}}$

$\large{\bf{ \longmapsto \frac{39400}{40000} \times 100}}$

$\large\underline{\bf{ \longmapsto98.5\%}}$

$\large\underline{\bf{ \longmapsto100\% - 98.5\%}}$

$\large\underline{ \boxed{\bf{ \implies1.5\%}}}$

Hence, the milkman loses 1.5% on the total trade.