Question

7. A painting 40 cm long and 28 cm wide is painted on a cardboard such that there is a
margin of 2 cm along each of its sides. Find the total area of the margin.
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Answer 1

Given,

• Length of the painting with the margin (l) = 40 cm

• Width of the painting with the margin (w) = 28 cm

We know,

$\boxed{\sf{Area=length\times width}}$

$\sf{\implies a=40\times 28}$

$\sf{\implies a=1120 \ cm^2}$

• Length of the painting without the margin (L).

$\sf{\implies L=40-(2+2)}$

$\sf{\implies L=40-4}$

$\sf{\implies L=36 \ cm}$

• Width of the painting without the margin (W).

$\sf{\implies W=28-(2+2)}$

$\sf{\implies W=28-4}$

$\sf{\implies W=24 \ cm}$

• Area of the painting without the margin (A).

$\sf{\implies A=L\times W}$

$\sf{\implies A=36\times 24}$

$\sf{\implies A=864 \ cm^2}$

Now we have to find the total area of the margin.

$\sf{\implies Total \ area=a-A}$

$\sf{\implies Total \ area=1120-864}$

$\sf{\implies Total \ area=256 \ cm^2}$

$\huge{\boxed{\sf{ Total \ area=256 \ cm^2}}}$