Physics, asked by ksushma14283, 6 months ago

7. A particle is moving on a circular path with constant
speed v. It moves between two points A and B,
which subtends an angle 60° at the centre of circle.
The magnitude of change in its velocity and change
in magnitude of its velocity during motion from A to
B are respectively
(1) Zero, Zero
(2) V, 0
(3) 0, v
(4) 2V, v​

Answers

Answered by Anonymous
63

Answer:

 \rm (2) \ v, 0

Explanation:

Velocity of particle at point A:

 \rm \overrightarrow{v}_A = v \hat{j}

Velocity of particle at point B:

 \rm \overrightarrow{v}_B = -v \ sin\theta \hat{i} + v \ cos \theta \hat{j}

Change in velocity:

 \rm \leadsto \Delta \overrightarrow{v} = \overrightarrow{v}_B - \overrightarrow{v}_A \\  \\  \rm \leadsto \Delta \overrightarrow{v} = - v \: sin \theta \hat{i} + v \: cos \theta \hat{j} - v \hat{j} \\  \\  \rm \leadsto \Delta \overrightarrow{v} = - v \: sin \theta \hat{i}  -  v (1 - cos \theta) \hat{j}  \\  \\  \rm \leadsto | \Delta \overrightarrow{v} |  =  \sqrt{(- v \: sin \theta) ^{2}  + [ -  v ( 1 -  cos \theta)] ^{2} }  \\  \\ \rm \leadsto  \Delta v =  \sqrt{ {v}^{2} ( sin ^{2}  \theta  +  1  +  cos ^{2}  \theta  - 2cos \theta) }  \\  \\ \rm \leadsto  \Delta v =  \sqrt{ {v}^{2} ( 2  - 2cos \theta) } \\  \\  \rm \leadsto  \Delta v =  \sqrt{ 2{v}^{2} ( 1  - cos \theta) } \\  \\  \rm \leadsto  \Delta v =  \sqrt{4 {v}^{2}  {sin}^{2} \dfrac{ \theta}{2}  } \\  \\  \rm \leadsto  \Delta v =  2v \: sin \dfrac{ \theta}{2}

For  \rm \theta = 60\degree :

\rm \leadsto  \Delta v =  2v \: sin  \bigg(\dfrac{ 60 \degree}{2} \bigg)  \\  \\ \rm \leadsto  \Delta v =  2v \: sin 30 \degree \\  \\ \rm \leadsto  \Delta v =   \cancel{2}v  \times  \dfrac{ 1}{ \cancel{2}}  \\  \\ \rm \leadsto  \Delta v = v

 \therefore Magnitude of change in velocity (∆v) = v

Change in magnitude of its velocity during motion from A to B:

 \rm \implies   | \overrightarrow{v}_B |  - | \overrightarrow{v}_A |   \\  \\  \rm \implies v - v \\  \\  \rm \implies 0

Attachments:
Answered by sera44
22

Answer:

Explanation:

A particle is moving on a circular path with constant

speed v. It moves between two points A and B,

which subtends an angle 60° at the centre of circle.

The magnitude of change in its velocity and change

in magnitude of its velocity during motion from A to

B are respectively

(1) Zero, Zero

(2) V, 0

(3) 0, v

(4) 2V, v​

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