Question

7) A quadratic equation ax^2 + bx + c = 0 has
(i)two distinct real roots, if b^2 - 4ac > 0,
(ii) two equal roots (i.e., coincident roots), if b^2 - 4ac = 0,7
(iii) no real roots, if b^2 - 4ac <0.​

Answer 1

Answer:

The quadratic equation consists all your option.

Step-by-step explanation:

ax2+bx+c =0 have two distinct roots,equal and no real roots.

Answer 2

Answer:

HERE IS YOUR ANSWER MATE......;

In the aforementioned polynomial, let a2 = x.

Now, the polynomial becomes,

x^2 + 4x + 5

Comparing with ax^2 + bx + c,

Here, b^2 – 4ac = 4^2 – 4(1)(5) = 16 – 20 = -4

So, D = b2 – 4ac < 0

As the discriminant (D) is negative, the given polynomial does not have real roots or zeroes

Hope It's Helpful.....:)