Math, asked by krishnadwibedy4, 1 month ago

7. A soapcake measures 7 cm in length, 5 cm in breadth and 2.5 cm in height. How many soapcakes can be placed in a cardboard box whose length, breadth and height are, respectively, 56 cm, 40 cm and 25 cm?​

Answers

Answered by luyiesmathew
71

Answer:

640 nos

Step-by-step explanation:

size of soap

l = 7cm

b =5cm

h =2.5cm

volume occupied by one soap, v = lbh

v=7×5×2.5

=87.5cm^3

size of box,

L = 56cm

B = 40cm

H = 25cm

volume occupied by box,

V = LBH

V = 56×40×25

=56000 cm^3

no. of soap cakes can be placed in the bix,

= V/v

=56000/87.5

=640

Answered by MoodyCloud
136

Answer:

640 soup cakes .

Step-by-step explanation:

Given that,

Length, breadth and height of soap is 7 cm, 5 cm and 2.5 cm respectively.

Length, breadth and height of cardboard box is 56 cm, 40 cm and 25 cm respectively.

  • Soup cake and cardboard box are of cuboid shape.
  • We need to place soap cakes in cardboard box. So, For this we need volume of both objects.

We know,

Volume of cuboid = lbh

[Where, l, b h are length, breadth and height]

Volume of soup cakes :

→ Volume of soup cakes = 7 × 5 × 2.5

→ Volume of soup cakes = 87.5

Volume of soup cakes is 87.5 cm³.

Volume of cardboard box :

→ Volume of cardboard box = 56 × 40 × 25

→ Volume of cardboard box = 56000

Volume of cardboard box is 56000 cm³.

Now,

→ Number of soup cakes can be place = Volume of cardboard box/Volume of soup cakes

→ 56000/87.5

640

Thus,

640 soup cakes can be placed in cardboard box.

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