7. A solid cylinder is of height 15 cm and diameter 7 cm. Two equal conical holes ofradius 3 cm and height 4 cm are cut off, one from each circular end. Find the surface area of the remaining solid
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slant height of cone(l) =root {h^2+r^2}
=root {16+9}=5 cm
now ,
surface area of remaining solid =2pi.R.H+ 2pi.r.l
=2pi. (RH+rl)
=2 x 22/7 (15 x 7/2 +3 x 5)
= 2 x 22/7 x 135/2
=424.28 cm^2
=root {16+9}=5 cm
now ,
surface area of remaining solid =2pi.R.H+ 2pi.r.l
=2pi. (RH+rl)
=2 x 22/7 (15 x 7/2 +3 x 5)
= 2 x 22/7 x 135/2
=424.28 cm^2
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