Question

7. An element ‘X’ belongs to the 2nd period and the 15th group of the Modern Periodic Table.
(a) Identify the element ‘X’. Write its electronic configuration. (b) Write the word equation for its reaction with hydrogen.

Answer 1

Answer:

[a]The element 'X' is [N] nitrogen.

It's electronic configuration is 1s² 2s² 2p⁵

It belongs to 2nd period and 15th or 5th group.

[b] N2 + 3h ------- 2NH3.

Answer 2

Answer:

a)Element 'X'=Nitrogen 'N'

Electronic configuration=$1s^{2}2s^{2}2p^{3}$

b)$Nitrogen + 3\ moles\ of\ Hydrogen \rightarrow2\ moles\ of\ Ammonia$

Explanation:

a)The element 'X' that belongs to the 2nd period and 15th group of the modern periodic table is Nitrogen 'N'. Its valency is 3.

The atomic number of Nitrogen is 7.

Its electronic configuration is-(2,2,3)

$1s^{2}2s^{2}2p^{3}$

b)$N_{2}+3H_{2}\rightarrow 2NH_{3}$

Nitrogen reacts with 3 moles of Hydrogen to form 2 moles of Ammonia.

Word reaction for the reaction of nitrogen with Hydrogen is given below:

$Nitrogen + 3\ moles\ of\ Hydrogen \rightarrow2\ moles\ of\ Ammonia$