Question

7. An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.


Answer : Initial height =10
Final depth = -350 m
= -350 -10
= -360 m.
$1m = - 6 \\ - 360 = ? \: min \: \\ \\ \frac{ - 360}{ - 6} = \frac{60}{1} min \: \\ \\ = 1 \: hour \: answer \:$
hope you help ​

Answer 1

Answer:

InInitial height =10

Final depth = -350 m

= -350 -10

= -360 m.

$1m = - 6 \\ - 360 = ? \: min \: \\ \\ \frac{ - 360}{ - 6} = \frac{60}{1} min \: \\ \\ = 1 \: hour \: answer \:$