Computer Science, asked by jeffdeva, 1 year ago

7 by 11 of a number exceeds 2 by 5 of a number by 91 find the number

Answers

Answered by Anonymous

Let the number be x

ATQ

(7x/11)-(2x/5)=91

(35x-22x)/ 55=91

13x=91×55

x=(91×55)/13

x=7×55

x=385

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Answered by jaya1012

HELLO........FRIEND!!

THE ANSWER IS HERE,

Let the number be x.

$= > \: \frac{7x}{11 } = \frac{2x}{5} + 91$

$= > \: \frac{7x}{11} - \frac{2x}{5} = 91$

$= > \: \frac{35x - 22x}{55} = 91$

$= > \: \frac{13x}{55} = 91$

$= > \: x = 91 \times \frac{55}{13}$

x=385.

:-)Hope it helps u.

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