Question

7. Calculate the mass of 5L of SO2 at STP.​

Answer 1

Molar mass of a gas :-

$M = \frac{MRT}{PV }$                        $[n=\frac{m}{u}]$

$M=\frac{drt}{P}$                           $[PV=nrt]$

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Answer 2

First and foremost, keeping in mind that at room temperature, Oxygen is a gas.

So, Volume of Oxygen(O2) given = 5.6L.

Finding moles, Moles=Volume/22.4.

Moles= 5.6/22.4=1/4moles.

So, finding mass of O2= moles × Mol. Wt.

Mass( in grams) = 1/4 × 32. We have taken 32 as oxygen is is combined state O2, so 16×2=32.

We get, mass =8 grams. This is mass not active mass.

Active mass means molarity which will be

0.25/5.6= 0.044