Math, asked by akvskarthik2005, 6 months ago

A particle is moving in a circular path with constant speed V. when its angular displacement is 120 degrees then change in its velocity is ---

i)V/2 ii) (root 3 by 2)•V iii)V iv) root 3 • V​

Answers

Answered by Anonymous
2

Answer:

The particle starts from point P and after half rotation, it reaches at Q via path PMQ.

Distance covered by particle to reach at Q is d=πR

Answered by sk181231
22

Answer:

Distance covered by particle to reach at Q is D = Rπ

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