7. Calculate the mass of the photon with a wavelength
corresponding to the series limit of Balmer transitions of
the He ion in kg?
(A) 4.22x10-36
(B) 2.24x10-34
(C) 2.42x10-35
(D) 4.22x10-36
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Answer:
As in the question limit wavelength is given hence we know that the electron of this transition will jump from the shell given to the infinty.
So, we have to find the wavelength by using the formulae of wave number as R*Z^2(1/4) as the shell is 2 in balmer series value of R=1.0968*10^(7) and Z of He is 2.
Thus, the on getting the wave number we will also know the wavelength as λ=1/(1.0968*10^(7)) = 0.91174*10^-7.
Putting the value in the debroglie equation will give us the answer.
We, know that the velocity of the light is 3*10^8 m/s.
Hence, λ=h/mv.
m= h/λv.
m=6.626*10^-34 / 0.91174*10^-7*3*10^8.
m= 6.626*10^-34/27.3522.
m = 2.42*10^-35Kg.
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