Math, asked by DHAVALS9429, 7 months ago

7 cos 55° / 3 sin 35° 85°) - 4(cos 70° cosec 20°) / 3(tan 5° tan 25° tan 45° tan 65° tan = 1

Answers

Answered by itsbiswaa

1

Answer:

cos557sin35−4(cos70csc20)7(tan5tan25tan45tan65tan85) ... From table we know, sin(90−θ)=cosθ,tan(90−θ)=cotθ,cscθ=1sinθ

Step-by-step explanation:

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