Question

The inner and outer surfaces of a 5-m x 6-m brick wall of thickness 30 cm and thermal
conductivity 0.69 W/(m. °C) are maintained at temperatures of 20°C and 5°C, respectively. Determine the
rate of heat transfer through the wall, in W.​

Answer 1

Explanation:

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Answer 2

Answer:

The heat transfer through the wall is 1035 W

Explanation:

Given,

• The thickness of wall = 30 cm = 0.3 m
• thermal conductivity = 0.69 W/m °C
• The inner temperature = 20°C
• The outer temperature = 5°C

To find:

• The heat transfer through the wall

Assumption:

• The temperature of the wall and the two thermal properties of the wall remain constant under steady operating condition.

Solution:

• The temperature was maintained at the inner and outer surface.
• The heat transfer occurs through the wall.

$Heat transfer through the wall Q= k A \frac{T_{1} - T_{2} }{L}$   .......................(1)

T₁ = inner temperature

T₂ = Outer temperature

Substitute all the values in equation(1)

Q = (0.69) W/m °C × (5×6 m²) $\frac{20-5}{0.3m}$ °C

Q = 0.69 × 30 × 50

Q = 1035 W

Therefore the heat transfer through the wall is 1035 W.

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