7. Eight taps through which water flows at the same rate can fill a tank in 27 minutes. If
two taps go out of order, how long will the remaining taps take to fill the tank?
Answers
Answered by
6
Answer:
Eight taps through which water flows at the same rate can fill a tank in = 27 minutes.
So, 1 tap through which water flows can fill a tank in = 27×8 minutes
Given,
Two taps go out of order then,
remaining taps = 8–2=6 taps
∴ 6 taps through which water flows can fill a tank in =
27×8
____minutes
6
=36 minutes
hope this helps u
pls follow me and mark my answer as brainliest
Answered by
8
Answer:
36 minutes
Step-by-step explanation:
Eight taps through which water flows at the same rate can fill a tank in = 27 minutes.
So, 1 tap through which water flows can fill a tank in = 27×8 minutes
Given,
Two taps go out of order then,
remaining taps = 8–2=6 taps
∴ 6 taps through which water flows can fill a tank in = 27×8/6
minutes
=36 minutes
Marks me as brainliest
Similar questions