Math, asked by chirag613887, 5 months ago

7. Eight taps through which water flows at the same rate can fill a tank in 27 minutes. If
two taps go out of order, how long will the remaining taps take to fill the tank?​

Answers

Answered by Anonymous
6

Answer:

Eight taps through which water flows at the same rate can fill a tank in = 27 minutes.

So, 1 tap through which water flows can fill a tank in = 27×8 minutes

Given,

Two taps go out of order then,

remaining taps = 8–2=6 taps

∴ 6 taps through which water flows can fill a tank in =

27×8

____minutes

6

=36 minutes

hope this helps u

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Answered by aagmanpal35
8

Answer:

36 minutes

Step-by-step explanation:

Eight taps through which water flows at the same rate can fill a tank in = 27 minutes.

So, 1 tap through which water flows can fill a tank in = 27×8 minutes

Given,

Two taps go out of order then,

remaining taps = 8–2=6 taps

∴ 6 taps through which water flows can fill a tank in = 27×8/6

minutes

=36 minutes

Marks me as brainliest

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