AD and BC are equal perpendiculars to line segment ab show that CD bisects AB.
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Step-by-step explanation:
Given,
AD and BC are perpendiculars of AB.
To prove:
CD bisects AB
∠BOC = ∠DOC ( because Vertically opposite angles )
DA = BC
∠B = ∠A = 90°
So, by AAS congruence rule, ΔBOC ≅ ΔOAD
So now, CO = OD
so, it bisects AB on point 'O'
OA = OB [ by CPCT]
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AAS - ANGLE ANGLE SIDE
CPCT - CORRESPONDING PARTS OF CORRESPONDING TRIANGLES (ARE EQUAL)
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