Question

7. Estimate the force required for punching a 25 mm diameter hole through a
3.2 mm thick annealed titanium alloy Ti-6A1-4V sheet at room temperature. The
UTS for this alloy can be assumed to be 1000 MPa.​

Answer 1

I don't no this answer thanks

Answer 2

Given:

Diameter of the hole (D)$=25\ mm$$=1\times inch$

The Thickness of the sheet (t)$=32\ mm$$=\dfrac{1}{8}$

The tensile strength of titanium alloy at room temperature (σ$_{t}$)$=1000\ Mpa$

shear strength of titanium alloy at room temperature(T)$=44\ Gpa=44000\ MPa$

To Find:

Punching force (F)=?

Solution:

Use the formula of punching force

$F=0.7\times T\times L\times UTS\\=[0.7\times\dfrac{1}{8}\times\pi \times1\times140000 ]\\=38484.5 lbf$

Therefore, the force required for punching is 38484.5 lbf or $1.8\times10^{5}\ N$.