Question

7. Father’s present age is 4 times Soham’s age. After 5 years, father’s age will be 3 times Soham’s age. Find their present ages.

Answer 1

Hii !


Let present age of soham be X years.



Present age of Father = 4X years.





After 5 years age of soham = ( X + 5 ) years.


After 5 years age of Father = ( 4X + 5 ) years.




A/C


4X + 5 = 3 ( X + 5 )



4X + 5 = 3X + 15


4X - 3X = 15 -5



X = 10 years


Present age of soham = X = 10 years.


And,

Present age of Father = 4X = 40 years.

Answer 2

Let, the present age of Soham be x
and the present age of Father be 4x

After 5 years Soham age =( x+5) Years
After 5 years Father age = (4x+5) Years

A/Q,

(4x+5) = 3(x+5)
=> 4x+5 = 3x+15
=> 4x-3x = 15-5
=> x = 10 years


Hence, Present age of Soham = x = 10 years.
Then, Fatger's age = 4x = 40 years.


Be Brainly