7. Find a vector of magnitude 18 which is
perpendicular to both the vectors 41 - +3k and
- 2 + 7 - 2 k.
(Ans. - 6 1 + 12 + 12 )
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Explanation:
A vector perpendicular to the given two vectors will be in the direction of their cross product. The unit vector in the direction of their cross product will be( cross product can be found by using
the method of determinant
−1
2
+2
2
+2
2
−i+2j+2k
=
3
−i+2j+2k
=
3
18
(−i+2j+2k)=
Ans :- −6i+12j+12k
hope it may help you
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