Question

7. Find the area of a trapezium, whose two parallel sides are 3 m and 4 m 2 dm respective
Each of the other sides of the trapezium is 2 m.​

Answer 1

Area of Trapezium

= $A=\frac{a+b}{2} h$

Parallel sides = 3cm and 4cm

Other 2 sides = 2cm

Therefore height of the trapezium

= (hypotenuse)^2 - (base)^2 = (4 - 1)cm^2 = $\sqrt{3}$

Area

$\frac{3+4}{2} \sqrt{3} \\= 3.5\sqrt{3} \\= 6.062$