Question

7. Find the area of the equilateral triangle whose each side is: (i) 12 cm, (ii) 5 cm.
​

Answer 1

Answer: Thus, the area of the equilateral triangle whose each side is 12  is $\frac{144\sqrt{3} }{4} cm^{2}$

Thus, the area of the equilateral triangle whose each side is 5 is $\frac{25\sqrt{3} }{4} cm^{2}$

Step-by-step explanation:

Side of equilateral Triangle is 5cm

The area of triangle is given by=$\sqrt{} \frac{3}{4}a^{2}$

=$=\sqrt{} \frac{3}{4}*5^{2}\\\sqrt{} \frac{3}{4}*25$

=$\frac{25\sqrt{3} }{4} cm^{2}$

Side of equilateral Triangle is 12cm

The area of triangle is given by=$\sqrt{} \frac{3}{4}a^{2}$

=$=\sqrt{} \frac{3}{4}*12^{2}\\\sqrt{} \frac{3}{4}*144$

=$\frac{144\sqrt{3} }{4} cm^{2}$

Thus, the area of the equilateral triangle whose each side is 12  is $\frac{144\sqrt{3} }{4} cm^{2}$

Thus, the area of the equilateral triangle whose each side is 5 is $\frac{25\sqrt{3} }{4} cm^{2}$