Question

7. Find the compound interest on 325,000 at 16% p.a. for 6 months
compounded quarterly.
- नाव टा से महीने के लिा चकतात याल .​

Answer 1

$\bf{\huge{\boxed{\underline{\tt{ANSWER\::}}}}}$

C.I. = Rs.26520

$\bf{\red{Given}}\begin{cases}\sf{Principal,[P]\:=\:Rs.325000}\\ \sf{Rate,[R]\:=\:16\%}\\ \sf{Time,[n]\:=\:6\:months}\end{cases}$

$\bf{\Large{\underline{\underline{\bf{To\:Find\::}}}}}$

The compound Interest.

$\bf{\Large{\underline{\underline{\tt{\green{Explanation\::}}}}}}$

$\bullet{\sf{Quarter\:Time\:=\:\dfrac{6}{12} *4=\cancel{\dfrac{24}{12} }=2\:years}}$

$\bullet{\sf{Quarter\:rate\:=\:\cancel{\dfrac{16}{4}} \%\:=\:4\%}}$

$\boxed{\begin{minipage}{7cm} \textbf{FORMULA\::}\\ \\ \sf{Compound \:Interest \:= Amount - Principal}\\ \\ \sf{A\: =\: P(1+\dfrac{R}{100} )^{n} } \end{minipage}}$

A/q

$|\implies\:\sf{A\:=\:P\bigg(1+\dfrac{R}{100} \bigg)^{n} }\\\\\\\\|\implies\sf{A\:=\:325000\bigg(1+\dfrac{4}{100} \bigg)^{2} }\\\\\\\\|\implies\sf{A\:=\:325000\bigg(1+\dfrac{1}{25} \bigg)^{2} }\\\\\\\\|\implies\sf{A\:=\:325000\bigg(\dfrac{25+1}{25} \bigg)^{2} }\\\\\\\\|\implies\sf{A\:=\:\cancel{325000}*\dfrac{26}{\cancel{25}} *\dfrac{26}{\cancel{25}} }\\\\\\\\|\implies\sf{A\:=\:Rs.(520*26*26)}\\\\\\\\|\implies\sf{\red{A\:=\:Rs.351520}}$

Now,

$\longmapsto\sf{Compound\: Interest\:=\:Amount - Principal}\\\\\\\\\longmapsto\sf{Compound\:Interest\:=\:Rs.(351520\:-\:325000) = Rs.26520}$

Answer 2

Step-by-step explanation:

Given,

Principal (P) = ₹325000

Rate Of Interest (R) = 16%

Time = 6 months = 1/2 year

For compund quarterly,

Amount (A) = P (1 + R/4×100)⁴ⁿ

Amount = 325000(1+ 16/400)⁴×¹/²

Amount = 325000(1+0.04)²

Amount = ₹351520

Compound Interest = Amount - Principal = ₹26520.