7. Find the coordinates of the point which divides the line segment joining (-3, 5) and
(4, -9) in the ratio 1 : 6 internally.
Answers
Answered by
9
Hi ,
*******************************************
Division of a segment internally:
The point which divides the line
joining A( x1 , y1 ) , B( x2 , y2 ) in the
ratio m : n internally is
( mx2 + nx1 / m + n , my2 + ny1/m+n )
*******************************************
Let P( x , y ) the required point ,
Using the section formula
A( x1 , y1 ) = ( -3 , 5 )
B( x2 , y2 ) = ( 4 , -9 )
m : n = 1 : 6
x = ( 1 × 4 + 6 × -3 )/( 1 + 6 )
= ( 4 - 18 )/7
= -14/7
= -2
y = ( 1 × -9 + 6 × 5 )/( 1 + 6)
= ( - 9 + 30 )/7
= 21/7
= 3
P( x , y ) = ( -2 , 3 )
I hope this helps you.
: )
*******************************************
Division of a segment internally:
The point which divides the line
joining A( x1 , y1 ) , B( x2 , y2 ) in the
ratio m : n internally is
( mx2 + nx1 / m + n , my2 + ny1/m+n )
*******************************************
Let P( x , y ) the required point ,
Using the section formula
A( x1 , y1 ) = ( -3 , 5 )
B( x2 , y2 ) = ( 4 , -9 )
m : n = 1 : 6
x = ( 1 × 4 + 6 × -3 )/( 1 + 6 )
= ( 4 - 18 )/7
= -14/7
= -2
y = ( 1 × -9 + 6 × 5 )/( 1 + 6)
= ( - 9 + 30 )/7
= 21/7
= 3
P( x , y ) = ( -2 , 3 )
I hope this helps you.
: )
Similar questions