Question

7. Find the general value of from the following
equations :
(1) 2(cos square theta - sin square theta)=1​

Answer 1

hey mate

given here

1) 2(cos ^2 x - sin^2 x)=1

we know that ,

2cos2x =(cos ^2 x - sin^2 x)

so,

2(cos2x)=1

cos2x=1/2

cos2x=cos(2nπ+π/3)

2x=(2nπ+π/3)

x=(2nπ+π/3)1/2

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