Math, asked by srivanigillepally, 1 month ago

7. Find the perimeters of ODABE id the rectangle BCDE in this figure. Which figure has greater perimeted and by how much? 34 zona fcmܝ c 0 1 2 3 cm E​

Answers

Answered by mananshinde777
0

Answer:

Perimeter of ΔABE = AB+BE+AE

= 3

3

1

+2

5

1

+4

3

2

=

3

10

+

5

11

+

3

14

=

15

50+33+70

=

15

153

=10

15

3

cm

Perimeter of Rectangle BCDE = 2(l+b)

=2(2

5

1

+1

3

2

)

=2(

5

11

+

3

5

)

=2(

15

33+25

)

=2(

15

58

)

=

15

116

=7

15

11

cm

So,ΔABE has greater perimeter

Difference of perimeter =

15

153

15

116

=

15

37

=2

15

7

cm

Hence ΔABE has greater perimeter by =2

15

7

cm

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