Question

7. Find the point on the x-axis which is equidistant from (2,-5) and (-2,9).

can i get solution of this question from (swags0988)​

Answer 1

Answer:

answer to the above question is given in the attachment

Answer 2

Step-by-step explanation:

Hi, diya☺ here we go

Given points A(2, -5) and B(-2, 9)

Let the points be P(x, 0).

So, AP = PB and AP² = PB²

= (x - 2)² + (0 + 5)² = (x + 2)² + (0 - 9)²

= x² + 4 - 4x + 25 = x² + 4 + 4x + 81

= x² + 29 - 4x = x² + 85 + 4x

= - 4x - 4x = 85 - 29

= - 8x = 56

= x = -7

Hence, point on the x - axis which is equidistant

from (2, -5) and ( - 2, 9) is ( -7, 0).