Question

7. Find the velocity v, if liquid flowing in streamline
manner
A = 1 cm
v. = 4 m/s
A, = 2 cm
v. = 8 m/s
A = 1.5 cm
(1) 4 m/s
(2) 8 m/s
(3) 12 m/s
(4) 16 m/s

Answer 1

The velocity is 8 m/s.

(2) is correct option.

Explanation:

Given that,

Area of input cross section = 1 cm

Velocity of input = 4 m/s

Area of first output cross section = 2 cm

Velocity of first output = 8 m/s

Area of second  output cross section = 1.5 cm

We need to calculate the velocity

Using formula of continuity

$A_{2}v_{2}=A_{1}v_{1}+A_{3}v_{3}$

Put the value into the formula

$2\times10^{-2}\times8=1\times10^{-2}\times4+1.5\times10^{-2}\times v_{3}$

$v_{3}=\dfrac{2\times10^{-2}\times8-1\times10^{-2}\times4}{1.5\times10^{-2}}$

$v_{3}=8\ m/s$

Hence, The velocity is 8 m/s.

Learn more :

Topic = continuity equation

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