Question

7. For the reaction,
N2(g) + 3H2(g) + 2NH3(8)
At 400 K, K, = 41. Find the value of K, for each of the
following reactions at same temperature :
(i)
2NH3(g) = N2(g) + 3H2(8)
(ii) (4)N2(8) +(2)H2(8) NH3(8)
2N2(g) + 6H2(g) = 4NH3(8)
[Ans. (i) 0.024 (ii) 6.4
(ii) 6.4 (iii) 1.68 x 10']​

Answer 1

Answer:

Hope you get the solution

Explanation:

7. For the reaction,

N2(g) + 3H2(g) + 2NH3(8)

At 400 K, K, = 41. Find the value of K, for each of the

following reactions at same temperature :

(i)

2NH3(g) = N2(g) + 3H2(8)

(ii) (4)N2(8) +(2)H2(8) NH3(8)

2N2(g) + 6H2(g) = 4NH3(8)

[Ans. (i) 0.024 (ii) 6.4

(ii) 6.4 (iii) 1.68 x 10']

7. For the reaction,

N2(g) + 3H2(g) + 2NH3(8)

At 400 K, K, = 41. Find the value of K, for each of the

following reactions at same temperature :

(i)

2NH3(g) = N2(g) + 3H2(8)

(ii) (4)N2(8) +(2)H2(8) NH3(8)

2N2(g) + 6H2(g) = 4NH3(8)

[Ans. (i) 0.024 (ii) 6.4

(ii) 6.4 (iii) 1.68 x 10']

7. For the reaction,

N2(g) + 3H2(g) + 2NH3(8)

At 400 K, K, = 41. Find the value of K, for each of the

following reactions at same temperature :

(i)

2NH3(g) = N2(g) + 3H2(8)

(ii) (4)N2(8) +(2)H2(8) NH3(8)

2N2(g) + 6H2(g) = 4NH3(8)

[Ans. (i) 0.024 (ii) 6.4

(ii) 6.4 (iii) 1.68 x 10']

7. For the reaction,

N2(g) + 3H2(g) + 2NH3(8)

At 400 K, K, = 41. Find the value of K, for each of the

following reactions at same temperature :

(i)

2NH3(g) = N2(g) + 3H2(8)

(ii) (4)N2(8) +(2)H2(8) NH3(8)

2N2(g) + 6H2(g) = 4NH3(8)

[Ans. (i) 0.024 (ii) 6.4

(ii) 6.4 (iii) 1.68 x 10']

7. For the reaction,

N2(g) + 3H2(g) + 2NH3(8)

At 400 K, K, = 41. Find the value of K, for each of the

following reactions at same temperature :

(i)

2NH3(g) = N2(g) + 3H2(8)

(ii) (4)N2(8) +(2)H2(8) NH3(8)

2N2(g) + 6H2(g) = 4NH3(8)

[Ans. (i) 0.024 (ii) 6.4

(ii) 6.4 (iii) 1.68 x 10']

7. For the reaction,

N2(g) + 3H2(g) + 2NH3(8)

At 400 K, K, = 41. Find the value of K, for each of the

following reactions at same temperature :

(i)

2NH3(g) = N2(g) + 3H2(8)

(ii) (4)N2(8) +(2)H2(8) NH3(8)

2N2(g) + 6H2(g) = 4NH3(8)

[Ans. (i) 0.024 (ii) 6.4

(ii) 6.4 (iii) 1.68 x 10']

7. For the reaction,

N2(g) + 3H2(g) + 2NH3(8)

At 400 K, K, = 41. Find the value of K, for each of the

following reactions at same temperature :

(i)

2NH3(g) = N2(g) + 3H2(8)

(ii) (4)N2(8) +(2)H2(8) NH3(8)

2N2(g) + 6H2(g) = 4NH3(8)

[Ans. (i) 0.024 (ii) 6.4

(ii) 6.4 (iii) 1.68 x 10']

7. For the reaction,

N2(g) + 3H2(g) + 2NH3(8)

At 400 K, K, = 41. Find the value of K, for each of the

following reactions at same temperature :

(i)

2NH3(g) = N2(g) + 3H2(8)

(ii) (4)N2(8) +(2)H2(8) NH3(8)

2N2(g) + 6H2(g) = 4NH3(8)

[Ans. (i) 0.024 (ii) 6.4

(ii) 6.4 (iii) 1.68 x 10']