7) for x²+4x +40 o find value of discriminant
(1)0 (2)4 (3)-4 (4)5
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(X+2) (x+2) =0
X= -2
(-2)² + 4(-2 ) +4=0
4 - 8 + 4 = 0
So therefore Zero is the answer
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Answered by
0
Answer:
answer is 0
Step-by-step explanation:
according to formula
D = b^2 - 4ac
= (4)^2-4(1)(40)
= 16 - 160
D = -144
D = √144
D = + or - 12
here D < 0
answer :0
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