Question

7. Given that log2 with base 10= x and log3 with base 10= y, the value of log60 with base 10is expressed as
(a) x - y +1
(b) x + y +1 (c) x - y-1
​

Answer 1

Answer:

Option (c)

Step-by-step explanation:

Given:

$log_{10}(2) = x \\ log_{10}(3) = y$

We know that,

$1 = log_{10}(10)$

We also know that,

$log_{a}(m) + log_{a}(n) = log_{a}(mn)$

So now,

$x + y + 1 \\ log_{10}(2) + log_{10}(3) + log_{10}(10) \\ log_{10}(2 \times 3 \times 10) \\ log_{10}(60)$