Question

7. If 5-digit number 672xy is divisible by 3,7 and 11, then what is the value of 5x+6y? यदि 5 अंको की संख्या 672xy 3,7 और 11 से विभाज्य है, तो 5x+6y का मान क्या होगा

Answer 1

Answer:

| If the 5-digit number 538xy is divisible

by 3, 7 and 11, then the value of (x2 + y2) is:d :13

Answer 2

Given : 5-digit number $672xy$ is divisible by $3, 7$ and $11$.

To find : the value of $5x + 6y$

Step-by-step explanation:

It is given that, the number is divisible by $3, 7$ and $11$.

∴ L.C.M. of $3, 7$ and $11$ = $3*7*11$

                               = $231$

$5$ digit number is $672xy$.

As the $xy$ terms are present in ten's place and unit's place. Its biggest two digit value will $99$.

∴ $5$ digit number will be $67299$.

Now,  by dividing $67299$ by $231$, we get $78$ as remainder.

∴ Required $5$ digit number = $67299-78= 67221$

∴ value of $x=2$ and $y=1$

So, $5x+6y= 5(2)+6(1)$

                = $10+6$

                = $16$