Question

7. If A = 3x²-4x+1 , B = 5x²+3x-8 and C = 4x²-7x+3, then find :
B+C-A​

Answer 1

Answer:

given,

A=3x²-4x+1

B=5x²+3x-8

C=4x²-7x+3

then,

B+C-A

=5x²+3x-8+4x²-7x+3-3x²+4x-1

=9x²-4x-5-3x²+4x-1

=6x²-6

6x²=6

x²=1

x=1

here is your answer

Answer 2

We are asked to find the value of  B + C - A :

• Substituting the values :

$\sf{\left(5x^2+3x-8\right)+\left(4x^2-7x+3\right)-\left(3x^2-4x+1\right)}$

$\sf{=5x^2+3x-8+4x^2-7x+3-\left(3x^2-4x+1\right)}$

$\sf{=5x^2+3x-8+4x^2-7x+3-3x^2+4x-1}$

$\sf{=5x^2+4x^2-3x^2+3x-7x+4x-8+3-1}$

$\sf{=6x^2+3x-7x+4x-8+3-1}$

$\sf{=6x^2-8+3-1}$

$\bf{=6x^2-6}$