Question

-7. If cosec - cot 0 = x, then cosec 0 + cot 0 =​

Answer 1

Answer:

(1/x)

Step-by-step explanation:

PLEASE FIND THE ATTACHMENT.

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Answer 2

$\huge{ANSWER}$

$\cosec\theta+\cot\theta=\dfrac{1}{x}$

$\mathcal{NOTE :-}$

$</p><p>\boxed{\begin{minipage}{7 cm}Fundamental Trigonometric Identities \\ \\ \sin^2\theta + \cos^2\theta=1 \\ \\1+\tan^2\theta = \sec^2\theta\\\\1+\cot^2\theta = \text{cosec}^2 \, \theta\end{minipage}}$

$\huge\underline{Solution}$

Using the identity,

$1+\cot^2\theta = \cosec^2\theta$

$\cosec^2\theta-\cot^2\theta=1$

Using the identity $a^{2}-b{2} = (a+b)(a-b)$

$\cosec^2\theta-\cot^2\theta=1$

$(\cosec\theta-\cot\theta)(\cosec\theta+\cot\theta)=1$ ---(1)

Given , $\cosec\theta-\cot\theta=x$

Putting the value , $\cosec\theta-\cot\theta=x$ in (1) ,

We get , $\cosec\theta+\cot\theta=\dfrac{1}{x}$