Question

7. If the energy of a photon is given as 3.03 * 10
then, the wavelength (a) of the photon is:
(a) 6.56nm
(b) 65.6nm
(c) 656nm
(d) 0.656nm​

Answer 1

we know that

E=hu

3.03*10^-19=(6.62*10^-34)*u

u=4.57*10^14

λ=c/u

λ=(3.0*10^8)/(4.57*10^14)

λ=6.56*10^-7m

λ=656nm

Answer 2

Answer:

ΔE=hc/λ  or  λ=hc/ΔE

=  6.62×10^−34 × 3×10^8  / 3.08×10^−19

=656nm