7.-If the point P(k-1, 2) is equidistant from the points
A(3,k) and B(k,5), find the values of k.
Answers
Answered by
7
Answer:
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Step-by-step explanation:
Answer
Correct option is
B
k=1,5
we have,
AP=BP
So by distance formula we have,
Distance between two points =
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
AP
2
=BP
2
(
(k−1−3)
2
+(2−k)
2
)
2
=(
(k−1−k)
2
+(2−5)
2
)
2
(k−4)
2
+(2−k)
2
=1+9
k
2
+16−8k+4+k
2
−4k=10
2k
2
−12k+20=10
k
2
−6k+5=0
(k−5)(k−1)=0
k=1,5
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