Question

7. If x = 2, y = -1 and z = 3, then the value of expression 3x2y + 5xy2 + 6yz2 + 2xyz is​

Answer 1

• We have to evaluate the above expression by using the given data.

              Given data:- $x=2,y=-1,z=3.$

              To find:-  $3x^{2} y+5xy^{2} +6yz^{2} +2xyz.$

              Solution:-

• To solve the above equation we will follow the BODMAS rule.

• BODMAS is an order of mathematic operations.

• BODMAS rule is to be followed while solving expressions in mathematics. It stands for,

           B= bracket

           O= order of power or rules

           D= division

           M= multiplication

           A= addition

           S= subtraction

• Now put the values x,y, and z in the given equation we get,

        $3x^{2} y+5xy^{2} +6yz^{2} +2xyz\\=>3(2)^{2} (-1)+5(2)(-1)^{2} +6(-1)(3)^{2} +2(2)(-1)(3)\\=>(-12)+(-20)+(-54)+(-12)\\=>-98.$

      Hence we will get the value is $-98.$