Question

7. In a crystalline solid having molecular formula A2B,
anions B are arranged in cubic close packed lattice and
cations A are equally distributed between octahedral
and tetrahedral voids. (i) What percentage of
octahedral voids is occupied ? (ii) What percentage of
tetrahedral voids is occupied ?​

Answer 1

Answer:

here's your answer

Explanation:

no. of B ions = 4 [cubic closed packed]

no . of octahedral voids = 4

no. of tetrahedral voids = 8

since the molecular formula is A2B

so no. of A ions = 8

4 in tetrahedral' 4 in octahedral

hence percentage of octahedral void occupied = 100

percentage of tetrahedral void occupied = 50