7. In a rhombus ABCD,
(a) If angleACD = 42°, then angleABC =
(b) If angleDOC = (7x + 6)", then x =
(c) If angleADB = 37, and angleDAC = (7x - 3) degree, then x
Answers
Answered by
1
Answer:
a)106 b)12 c)8
Step-by-step explanation:
please thinnk
Answered by
0
Answer:
(a) 96°
(b) 4cm
(c) 10cm
Step-by-step explanation:
(a) ACD = 42° So, BCD = 42×2 =84°
BCD=BAC
84+B+84+D = 360° ( Angle dum property of quadrilateral)
168+B+D =360°
B+D=360-168=192
B and D = 192÷2 = 96°
ABC=96°
(b) (7x+6)° = 90°
7x = 90-6
7x=84°
x=84÷7
x=12
(c) (7x-3)°=37°
7x=37-3
7x=34
x=34÷7
x=8.5
x=8
Similar questions