Math, asked by guriyadipanshu781, 1 month ago

7. In a rhombus ABCD,
(a) If angleACD = 42°, then angleABC =
(b) If angleDOC = (7x + 6)", then x =
(c) If angleADB = 37, and angleDAC = (7x - 3) degree, then x​

Answers

Answered by amankumarmth2006
1

Answer:

a)106 b)12 c)8

Step-by-step explanation:

please thinnk

Answered by khanaashiya4577
0

Answer:

(a) 96°

(b) 4cm

(c) 10cm

Step-by-step explanation:

(a) ACD = 42° So, BCD = 42×2 =84°

BCD=BAC

84+B+84+D = 360° ( Angle dum property of quadrilateral)

168+B+D =360°

B+D=360-168=192

B and D = 192÷2 = 96°

ABC=96°

(b) (7x+6)° = 90°

7x = 90-6

7x=84°

x=84÷7

x=12

(c) (7x-3)°=37°

7x=37-3

7x=34

x=34÷7

x=8.5

x=8

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