7. In a right angled triangle, one side is 42m and the difference of hypotenuse and
the other side is 14m. Find the lengths of both unknown sides. Calculate its area
by using Heron’s formula, for finding the area of a right triangle
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Solution: One side of the right triangular field = 42m Let the other side of the triangular field = x metres and its hypotenuse = y metres Since difference of lengths of hypotenuse and other = 14m ⇒ (y - x) = 14 m ⇒ y = ( x+ 14) m In a right angle triangle, ⇒ (Hypotenuse)2 = Side2 + Side2 [ By pythagoras theorem] ⇒ y2 = x2 + 422 ⇒ (x + 14)2 = x2 + (42)2 ⇒ x2 + 28x + 196 = x2 + 1764 ⇒ 28x = 1764 - 196 ⇒ 28x = 1568 ∴ x = 56 m Thus other side of the triangular field = 56 m We have, area of the triangle = ½ × Base × Height Now, Area of right triangular field = ½ × × 56 × 42 = 1176 m2
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